## [answered] A population consists of 15 items, 10 of which are acceptab

Hi-thanks for the awesome work on the other problems. Attached is a shorter version of questions I need answered by 7:00PM tomorrow December 18th.? I will pay \$10 since there are fewer questions.? :)? Thank you so much.

A population consists of 15 items, 10 of which are acceptable.

In a sample of four items, what is the probability that exactly three are acceptable? Assume the samples are drawn

without replacement. (Round your answer to 4 decimal places.) Probability According to the Insurance Institute of America, a family of four spends between \$400 and \$3,800 per year on all

types of insurance. Suppose the money spent is uniformly distributed between these amounts. a. What is the mean amount spent on insurance?

Mean \$ b. What is the standard deviation of the amount spent? (Round your answer to 2 decimal places.)

Standard deviation \$ c. If we select a family at random, what is the probability they spend less than \$2,000 per year on insurance per

Probability d. What is the probability a family spends more than \$3,000 per year? (Round your answer to 4 decimal places.)

Probability A normal population has a mean of 12.2 and a standard deviation of 2.5.

a. Compute the z value associated with 14.3. (Round your answer to 2 decimal places.)

Z b. What proportion of the population is between 12.2 and 14.3? (Round your answer to 4 decimal places.) Proportion c. What proportion of the population is less than 10.0? (Round your answer to 4 decimal places.)

Proportion A normal population has a mean of 80.0 and a standard deviation of 14.0.

a. Compute the probability of a value between 75.0 and 90.0. (Round intermediate calculations to 2 decimal

places. Round final answer to 4 decimal places.)

Probability b. Compute the probability of a value of 75.0 or less. (Round intermediate calculations to 2 decimal places.

Round final answer to 4 decimal places.)

Probability c. Compute the probability of a value between 55.0 and 70.0. (Round intermediate calculations to 2 decimal

places. Round final answer to 4 decimal places.)

Probability For the most recent year available, the mean annual cost to attend a private university in the United States was

\$26,889. Assume the distribution of annual costs follows the normal probability distribution and the standard

deviation is \$4,500.

Ninety-five percent of all students at private universities pay less than what amount? (Round z value to 2 decimal

Amount \$

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