[answered] A researcher wants to estimate the proportion of depressed

A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random sample of 225 individuals who had been taking the drug is questioned; 186 of them found relief from depression. Based upon this, compute a 99%

Confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then complete the table below.

Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places.

What is the lower limit of the 99% confidence interval?

What is the upper limit of the 99% confidence interval?

99% Confidence Interval for p

186

x

=

= 62/75 ? 0.826667 ? 0.827

n

225

Significance level = ? = 1? confidence = 1 ? 0.99 = 0.01

Critical z-value = z?/2 = z0.01/2 = z0.005 = 2.58 (closest...

Solution details:
STATUS
QUALITY
Approved

This question was answered on: Sep 18, 2020

Solution~0001003558.zip (25.37 KB)

This attachment is locked

We have a ready expert answer for this paper which you can use for in-depth understanding, research editing or paraphrasing. You can buy it or order for a fresh, original and plagiarism-free copy from our tutoring website www.aceyourhomework.com (Deadline assured. Flexible pricing. TurnItIn Report provided)

STATUS

QUALITY

Approved

Sep 18, 2020

EXPERT

Tutor