Question Details

[answered] Brock Leo Driskill Term Project 1 November 15, 2016 1. Case


I have attached the file with the questions please help.


Brock Leo Driskill

 

Term Project 1

 

November 15, 2016

 

1. 2. Case 1

 

Girls

 

Use of Social Networking Sites

 

Yes

 

166

 

No

 

34

 

Totals

 

200 Boys Totals 156

 

44

 

200 322

 

78

 

400 322

 

=0.805?80.5

 

400 The Probability that a teen uses social networking sites is

 

80.5%. 3. 166

 

=0.83?83

 

200 The Probability that a teen girl uses social networking sites is

 

83%.

 

4. Yes, this act would provide protection for teens. There is a high rise

 

in Social Networking sites by young teens they need this necessary

 

protection. There was a 80.5% of teens using social Networking sites

 

which is only a 19.5% of teen not using. Case 2

 

1. The Probability that at least one in a group of 10 New York

 

teenagers smoked in 2007 is .3821 or 38.2%.

 

P=.085 Q=.915

 

10 !

 

1

 

10?1

 

X=

 

?(1?.085) ?(.915)

 

( 10?1 ) ! 1 !

 

3628800

 

X=

 

? ( 1?.085 ) ? ( .4495622608 )

 

362880

 

X =10? .0382127922

 

X =.3821 2. The probability that at least one in a group of 10 New York City

 

teenagers smoked in 2001 is .3082 or 30.8%.

 

P=.176 Q=.824

 

10 !

 

1

 

10?1

 

X=

 

?(1?.176) ?(.824)

 

( 10?1 ) ! 1 !

 

3628800

 

X=

 

? ( 1?.176 )1 ? ( .824 )10?1

 

362880

 

X =10?(.030821769)

 

X =.3082 3. The probability that at least one in a group of 10 New York City

 

teenagers smoked in 1997 is .2188 or 21.9%.

 

P=.23 Q=.77

 

10 !

 

X=

 

? ( 1?.23 )1 ? ( .77 )10?1

 

( 10?1 ) ! 1 !

 

3628800

 

X=

 

? ( 1?.23 ) ? ( .0951516944 )

 

362880

 

X =10? ( .0218848897 )

 

X =.2188 4. There has been a significant change of 16.3% in teenage smoking

 

between 1997 and 2007. These changes do to I believe the harm

 

that cigarettes do to the human body and it is now harder for

 

teenagers to obtain cigarettes. Chase 3

 

Needed for problems ?=19.2 , ? =2.6 1. UNDERWEIGHT

 

For less than 5th percentile range.

 

P=0.05 Z=?1.645 (from table)

 

X =? +Z?

 

X =19.2+ (?1.645 ?2.6 )=14.923

 

x< 14.923 For less than 14.2 BMI range.

 

14.2?19.2 ?5

 

= =?1.92308??1.92

 

2.6

 

2.6 Looking at the table the value for that z score is 0.0274

 

The probability is 2.7%

 

HEALTHY WEIGHT

 

For between 5th and 85th Percentile Range.

 

P=0.05 Z=?1.645 (from table)

 

X =? +Z?

 

X =19.2+ (?1.645 ?2.6 )=14.923

 

1.03?1.04

 

?

 

?

 

P=0.85 Z=?

 

X =? +Z?

 

X =19.2+ (1.035 ? 2.6 )=21.891

 

21.891< x> 14.923 For Between 14.2 and 19.4 BMI Range

 

14.2?19.2 ?5

 

= =?1.92308??1.92

 

2.6

 

2.6 Going into excel the value for that z score is 0.0274

 

19.4?19.2 0.2

 

=

 

=0.076923?0.08

 

2.6

 

2.6 Going into excel the value for that z score is 0.5307

 

P=0.5307?0.0274=0.5033 The probability for between 14.2 and 19.4 is 50.3%.

 

OVERWEIGHT

 

For between 85th and 95th Percentile Range. 1.03?1.04

 

?

 

?

 

P=0.85 Z=?

 

X =? +Z?

 

X =19.2+ (1.035 ? 2.6 )=21.891

 

1.65+1.64

 

?

 

?

 

P=0.95 Z=?

 

X =? +Z?

 

X =19.2+ (1.645 ? 2.6 )=23.477

 

21.891< X >23.477 For between 19.4 and 22.2 BMI Range.

 

19.4?19.2 0.2

 

=

 

=0.076923?0.08

 

2.6

 

2.6 Going into excel the value for that z score is 0.5307

 

22.2?19.2 3

 

=

 

=1.15385?1.15

 

2.6

 

2.6 Going into excel the value for that z score is 0.8757

 

P=0.8757?0.5307=0.345 The probability for between 19.4 and 22.2 is 34.5%.

 

OBESE

 

For more than 95th Percentile Range.

 

1.65+1.64

 

?

 

?

 

P=0.95 Z=?

 

X =? +Z?

 

X =19.2+ (1.645 ? 2.6 )=23.477

 

X >23.477 For more than 22.2 BMI Range.

 

22.2?19.2 3

 

=

 

=1.15385?1.15

 

2.6

 

2.6 Going into excel the value for that z score is 0.8757

 

P=1?0.8757=0.1243 The probability for more than 22.2 is 12.4%.

 

2. The Health Officials concern is justifiable Because there are almost

 

just as many unhealthy children than there are overweight, obese,

 

and underweight children which comes in at 49.6% of the total children in the town. While the heathy children come in at 50.3%

 

only a 0.7 percentage difference between the two category?s.

 


Solution details:
STATUS
Answered
QUALITY
Approved
ANSWER RATING

This question was answered on: Sep 18, 2020

PRICE: $15

Solution~0001005816.zip (25.37 KB)

Buy this answer for only: $15

This attachment is locked

We have a ready expert answer for this paper which you can use for in-depth understanding, research editing or paraphrasing. You can buy it or order for a fresh, original and plagiarism-free copy from our tutoring website www.aceyourhomework.com (Deadline assured. Flexible pricing. TurnItIn Report provided)

Pay using PayPal (No PayPal account Required) or your credit card . All your purchases are securely protected by .
SiteLock

About this Question

STATUS

Answered

QUALITY

Approved

DATE ANSWERED

Sep 18, 2020

EXPERT

Tutor

ANSWER RATING

GET INSTANT HELP/h4>

We have top-notch tutors who can do your essay/homework for you at a reasonable cost and then you can simply use that essay as a template to build your own arguments.

You can also use these solutions:

  • As a reference for in-depth understanding of the subject.
  • As a source of ideas / reasoning for your own research (if properly referenced)
  • For editing and paraphrasing (check your institution's definition of plagiarism and recommended paraphrase).
This we believe is a better way of understanding a problem and makes use of the efficiency of time of the student.

NEW ASSIGNMENT HELP?

Order New Solution. Quick Turnaround

Click on the button below in order to Order for a New, Original and High-Quality Essay Solutions. New orders are original solutions and precise to your writing instruction requirements. Place a New Order using the button below.

WE GUARANTEE, THAT YOUR PAPER WILL BE WRITTEN FROM SCRATCH AND WITHIN YOUR SET DEADLINE.

Order Now